x=2x^2-5x+4

Solution for x=2x^2-5x+4 equation:

x=2x^2-5x+4

We move all terms to the left:

x-(2x^2-5x+4)=0

We get rid of parentheses

-2x^2+x+5x-4=0

We add all the numbers together, and all the variables

-2x^2+6x-4=0

a = -2; b = 6; c = -4;
Δ = b2-4ac
Δ = 62-4·(-2)·(-4)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2}{2*-2}=\frac{-8}{-4}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2}{2*-2}=\frac{-4}{-4}
=1
$